HOW TO CALCULATE IT WITH MATLAB
The matlab function file below shows how to transform the above solution into matlab language. Please note that we converted theta, the angle, from degree to radians by multiplying theta by pi/180
function[hmax,dmax,ttot]= trajectory(V0,theta,g)
%this function calculates the maximum height,total time of travel, and the
%maximum horizontal distance reached by a projectile
%v0=intial velocity
%g= acceleration due to gravity
%hmax= maximum height
%dmax= maximum horizontal distane
%ttot= total time of travel
V0x=V0*cos(theta*pi/180);
V0y= V0*sin(theta*pi/180);
hmax=V0y^2/2*g
ttot= 2*V0y/g
dmax=V0x*ttot
you can copy and paste the code to a matlab file and supply the input variable of your choice to see how it works
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